Details

    • Type: Story
    • Status: Done
    • Priority: Trivial
    • Resolution: Fixed
    • Affects Version/s: None
    • Fix Version/s: 0.9.9
    • Component/s: guacd
    • Labels:
    • Sprint:
      DEV 2015-11-13
    • Story Points:
      2

      Description

      I was wondering why is the 'listen()' syscall called from within the main loop while it seem only necessary to be called once just before the main loop.

      Reference:
      https://github.com/glyptodon/guacamole-server/blob/master/src/guacd/daemon.c#L616

      Best regards,
      Isaac B.

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            mike.jumper Michael Jumper added a comment -

            Hm... you're right. Reading over the listen() documentation, it does not need to be in the main loop. Only accept() needs to be there.

            My official reason for doing it this way is "oops".

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            mike.jumper Michael Jumper added a comment - Hm... you're right. Reading over the listen() documentation, it does not need to be in the main loop. Only accept() needs to be there. My official reason for doing it this way is "oops".

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              • Assignee:
                mike.jumper Michael Jumper
                Reporter:
                frenche Isaac Boukris
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                  Updated:
                  Resolved: